Var(Yi) = πi(1 − πi).Let π(x) = P(Y = 1 | x), the probability of success. The logistic function ensures predicted probabilities stay within [0, 1]:
π(x) = exp(β₀ + β₁x) / [1 + exp(β₀ + β₁x)]
     = 1 / [1 + exp(−(β₀ + β₁x))]
  
The odds of success are:
odds = π(x) / [1 − π(x)] = exp(β₀ + β₁x)
Taking the log gives the logit (log-odds):
log(odds) = log[π(x)/(1−π(x))] = β₀ + β₁x
exp(β₁) = 0.84, then a 1-unit increase in x reduces odds by 16%.Fitted model: 
    P(Y=1) = 1 / [1 + exp(−(10.875 − 0.17132 × Temp))]